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22
Herculito 8 Les juments de Diomède.py
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22
Herculito 8 Les juments de Diomède.py
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solutions = list()
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m1 = 7
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m2 = 11
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m3 = 13
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miam = 4*131
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for i in range(1, 21):
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for j in range(1, 21):
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for k in range(1, 21):
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if i*m1+j*m2+k*m3 == miam:
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solutions.append((i,j,k))
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min_sac = 60
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for solution in solutions:
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min_sac = min(solution[0]+solution[1]+solution[2], min_sac)
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best = (20, 20, 20)
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for solution in solutions:
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if solution[0]+solution[1]+solution[2] == min_sac and solution[2] < best[2]:
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best = solution
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print(best, best[0]*m1+best[1]*m2+best[2]*m3, best[0]+best[1]+best[2])
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